Could I get some help with the problem, please?

Question

What is the equation of the line that has a slope of -4/7 and passes through the point (0, -3)?

Answer 1

Hi Jonelle,

To find the equation of a line, you will typically need a point on the line and the slope. You are given both.

Using the Point-Slope formula Y-Y₁ = M(X-X₁). We can plug in the slope for M and the point given for your

(X₁, Y₁)

We then have Y- (-3) = -4/7(X-0)

This simplifies to Y+3 = -4/7 X. or Y= -4/7X - 3. If you need the line in Standard form Ax + By =C you just have to multiply all the terms by the Least common denominator which is 7. This gives you 7Y= -4x - 21. You then rewrite it as 4x + 7y = -21

Alternatively, you could have plugged in the slope and Y internet into the Slope-Intercept formula

Y = MX + B. The Y-intercept is always when X = 0. The given point has a zero for X which means that -3 must be the Y- intercept.

Y = -4/7 X + (-3). >. Y = -4/7X - 3

I hope this helps.

Audrey B.