AMDM Question (Mathematics)

Question

A school counts the number of students taking AMDM and find 214 students taking AMDM. They also count the number of students taking Physics and find 213 students taking the Physics. When they compare the two lists they find 131 student taking AMDM and Physics. What is the probability of a student taking AMDM given they are taking Physics. (Answer in decimal form rounded to the thousandth)

Answer 1

Let N be the total number of students.

P(student taking AMDM)=214/N

P(student taking the Physics)=213/N

P(student taking AMDM and Physics)=131/N

Conditional probability formula P(A I B)=P(A and B)/P(B) →

P(student taking AMDM I student taking Physics) =P(student taking AMDM and Physics)/P(student taking the Physics) = (131/N)/(213/N)=(131/N)*(N/213)=131/213=0.615