We would like to make a golden standard kilogram in the shape of circular cylinder. The density of gold is 19.32 g/cm3

Question

a) Find the volume of the kilogram standard of gold in cubic meter

b) In order to minimize the effect of surface contamination, the height of this golden standard kilogram is equal to its diameter. Find the height of this golden standard kilogram in mm.

Answer 1

For part a) we need to know how density, mass and volume are all connected. Very simply, density is the mass per unit volume or D = m / V. We know the density of gold, D = 19.32 g/cm3 and we know the total mass is m = 1kg. So we can then solve for the volume V.

For part b) we need to know the volume of a cylinder, which is pi*r^2*h, where r is the radius of the top/bottom circle and h is the heigh of the cylinder. We are told that the height is equal to the diameter, so h = d = 2r. We can then use the volume found in part A to calculate the radius and then the height.