The weight of meteorite A is 3 times the weight of meteorite B. If the sum of their weights is 92 ​tons, find the weight of each.

Answer 1

Hi Will.

To answer your question:

The weight of meteorite A is 3 times the weight of meteorite B. If the sum of their weights is 92 ​tons, find the weight of each.

We begin to assign variables and start with what we know:

Let meteorite A be A

Let meteorite B be B

Meteorite A is 3 times theweight of B, so A=3B

The sum of their weight is 92 tons, so A+B=92

Now we substitute the A with our 3B, write our equation and solve for B:

92=3B+B

92=4B

B=23

Next, solve for A:

92=A+23

A=69

And always check your work:

23x3=69✔

69+23=92✔

Answer 2

Solution:

Let the weight of meteorite A be W_a and weight of meteorite b be W_b, Now W_a = 3 W_b and the sum of their weights W_a+W_b = 92 tons. Substitute W_a = 3 W_b , 3 W_b + W_b = 92 tons, 4 W_b = 92 tons, divide both sides by 4, W_b = 92/4 = 23 tons, and W_a = 3 ( 23tons) = 69 tons

Ckeck: W_a+W_b = 92 tons, 69 tons + 23 tons = 92 tons Checks