Math help please!!

Question

Describe the domain of the function

f(x)=sqhareroot of 3x-5

Answer 1

Inside would be the second. That is, the -5 is also part of the square root.

Now then, since we're working with square roots, that means that our value needs to be greater than or equal to 0 (because there are no negative sqr rts), so think of √(3x-5) as:

3x - 5 = 0

3x = 5

x = ⁵/₃

So the domain is any number greater than ⁵/₃ (or 1 ²/₃), or ⁵/₃ to infinity

 

 

I'll assume that you really did mean that the -5 is not under the square root for this part. That is, I'll solve the other way as well.

that means 3x = 0

Divide both sides by 3:

x = 0

So in this case, the domain is 0 to infinity

 

That's why I has to ask how the problem is set up. Where that -5 lies changes the answer.