Determine the equation of a line perpendicular to y=-4/5x+7 and the same y-intercept as 7x-5y+2=0

Question

Determine the equation of a line perpendicular to y=-4/5x+7 and the same y-intercept as 7x-5y+2=0

Answer 1

y= 4x/5 + 2/5 is perpendicular to y=-4x/5 + 7 with the same y intercept as 7x-5y+2=0

to be perpendicular the slope must be the negative inverse. take -4/5, change the sign and flip the fraction upside down to get +5/4 The slope = the x coefficient when the equation is solved for y

7x-5y + 2 = 0 solved for y is

y = 7x/5 + 2/5 which is in slope intercept form y=mx+b where b is the y intercept