Tom K. answered 08/24/21
Knowledgeable and Friendly Math and Statistics Tutor
The standard deviation of the sample mean is σ/√n * √((N-n)/(N-1))
Note the presence of the finite sample correction factor.
Thus, s =8.3/√35 * √((350-35)/(350-1)) =1.33286644165475
Then, if we use the CLT to say the distribution is approximately normal,
P(x-bar <= 40) = Φ((40-37.6)/1.33286644165475) = Φ((40-37.6)/1.33286644165475) =
Φ((40-37.6)/1.33286644165475) = Φ(1.80063052455609) = .9641