The average of a and twice b is fifty-two. PLEASE answer quickly

Answer 1

"The average of a and twice b" can be translated to:

(a+2b)/2

set that equal to 52:

(a+2b)/2 = 52

Multiply both sides by 2:

2*((a+2b)/2) = 2*(52)

(a+2b) = 104

a = 104 - 2b

Using y for a and x for b, this makes the equation y = -2x + 104. This is a straight line with a y-intercept of 104 and a slope of -2. All points on this line satisfy the equation. We need more information to solve for a specific solution, such as a single value for either x or y, or an equation for an intersecting line.

Bob

Answer 2

To find an average, add the numbers together and divide by the number of numbers. The first number is "a" and the second number is "twice b" or "2b". The sum is "a + 2b" and then divide by the number of numbers (of which there are two) so (a + 2b)/2 = 52

There is not enough information in what you have given to find the value of either "a" or "b".