i do not know P(M > 30.8) = please help me

Question

A population of values has a normal distribution with  and . If a random sample of size  is selected,

1. Find the probability that a single randomly selected value is greater than 30.8. Round your answer to four decimals. P(X > 30.8) = Correct0.3264
2. Find the probability that a sample of size  is randomly selected with a mean greater than 30.8. Round your answer to four decimals. P(M > 30.8) = 

Answer 1

For mean M:

z = (M - mu)/(sigma/sqrt(n))

P(M > 30.8) = P( z > (30.8 - 23.6)/(16/sqrt(24)) = P(z > 2.2) = P(z < -2.2) = 0.0139.