
Jon S. answered 08/15/21
Patient and Knowledgeable Math and English Tutor
M = mean = 102.1
mu = 101.5
sigma = 1.6
n = 36
z = (102.1 - 101.5)/(1.6/sqrt(36)) = 2.25
P(M < 102.1) = P(z < 2.25) = 0.9878
Aiko L.
asked 08/15/218. Suppose the amount of a popular sport drink in bottles leaving the filling machine has a normal distribution with mean 101.5 milliliters (mL) and standard deviation 1.6. If 36 bottles are randomly selected, find the probability that the mean content is less than 102.1 mL
Jon S. answered 08/15/21
Patient and Knowledgeable Math and English Tutor
M = mean = 102.1
mu = 101.5
sigma = 1.6
n = 36
z = (102.1 - 101.5)/(1.6/sqrt(36)) = 2.25
P(M < 102.1) = P(z < 2.25) = 0.9878
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