
Jon S. answered 08/07/21
Patient and Knowledgeable Math and English Tutor
Selecting 4 balls from a box with 5 white balls and 4 blue balls. 9 balls total
- probability of getting two white balls
number of combinations of two white balls out of 5 * number of combination of 2 blue balls out of 4
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number of combinations of 4 balls out of 9
C(5,2) * C(4,2)/C(9,4) where C(x,y) = number of combination of y items out of x
2 probability of getting at most 1 white ball = probability of getting 0 white balls out of 4 + probability of getting 1 white ball out of 4:
C(5,0) * C(4,4)/C(9,4) + C(5,1)*C(4,3)/C(9,4)
3. Probability of getting at least 3 blue balls = probability of getting 3 blue balls out of 4 + probability of getting 4 blue balls out of 4:
C(5,1)*C(4,3)/C(9,4) + C(5,0)*C(4,4)/C(9,4)