Hello Dfghgrter.
the length is 4x
the width is x;
the perimeter is 4x +x +4x +x =80;
10x =80; x =10.
width = 10; length = 4times width = 10*4=40
Dfghgrter E.
asked 07/31/21The length of a rectangle is four times its width. If the perimeter of the rectangle is 80yd, find its area.
Hello Dfghgrter.
the length is 4x
the width is x;
the perimeter is 4x +x +4x +x =80;
10x =80; x =10.
width = 10; length = 4times width = 10*4=40
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