Math help I’m failing summer

Question

j(x)= 6x^4+2x^3-4x+4; find j(2)

Answer 1

Solution:

j(x) = 6x⁴ + 2x³ -4x +4 , find j(2) =? , all you have to do is substitute 2 for x

j(2) = 6(2)⁴ + 2(2)³ -4(2) + 4 = 6( 16) + 2(8) -4(2) + 4 = 96+16-8+4 = 108. So the value of the function j(x) is 108 when x=2 , and x = 2 has one and only one value for j(x) and that value is 108

Answer 2

j(x) = 6x^4 +2x^3 - 4x + 4 Just replace x by 2 to get

j(2) = 6(16) + 2(8) -4(2) + 4 = 96 +16 -8 + 4 = 108

j(2) = 108