
Yefim S. answered 06/30/21
Math Tutor with Experience
Limits of integration: 3 = 3 + 3sinθ; sinθ = 0, θ = 0, θ = π, θ = 2π;
Area A = 1/2∫0π32dθ + 1/2∫π2π(3 + 3sinθ)2dθ = 1/2·9π + 1/2∫π2π(9 + 18sinθ + 9sin2θ)dθ = 9π/2 +
9/2∫π2π(3/2 + 2sinθ - 1/2cos2θ)dθ = 9π/2 + 9/2(3/2θ - 2cosθ - 1/4sin2θ)π2π = 9π/2 + 9/2(3π - 2 - 3π/2 - 2) =
9/2(π + 3π/2 - 4) = 9(5π - 8)/4