The perimeter of a certain basketball court is 266ft, and it's length is 35ft more than its width. Find the dimensions of the cour.

Question

I don't know how to do this problem

Answer 1

Hi Demi,

 

Let the width of the court be x

 

The length is 35ft more than its width

Length=35+x

 

Perimeter of the basketball court= 266 ft

 

Perimeter of the basketball court = 2(length+width)

                                          266 = 2(35+x+x)

                                        266/2=35+2x

                                           133=35+2x

                                       133-35=35-35+2x

                                             98=2x

                                         98/2=2x/2

                                           49=x

 

So the width of the court is x=49ft

 

Length=35+x

         =35+49=84ft