4NH3 + 5O2 = 4NO + 6H2O If you made with 9.67 moles of H20, how many moles of NO were also produced?

Question

Already balanced equation I keep getting this one wrong and I'm not sure if it's my setup or if I'm dividing something wrong. Grateful for any help given!

Answer 1

Moles to moles takes one step.

The problem can be set up like this:

(9.67 mol H₂O) X (4 mol NO / 6 mol H₂O) = 6.45 mol NO

The balanced equation tells us that for every 6 moles of H₂O that are produced, 4 moles of NO are produced.

On your calculator, you can first multiply 9.67 X 4, which equals 38.68

Then go 38.68 divided by 6 and you will get 6.45

Answer 2

the underlying balanced equation here is

4NH3 ​+ 5O2 ​→ 4NO + 6H2​O

meaning that the molar ratio is 4 moles of NO for every 6 moles of H2O

from there then you want to convert the given value over by multiplying by the ratio

9.67 moles H2O x (4 moles NO / 6 moles H2O) = 6.45 moles NO

meaning that 6.45 moles of NO were produced in this scenario