Jacob N. answered • 06/12/21

25 years of experience teaching high school chemistry!

Good afternoon, Maggie. This problem can be solved using three-step stoichiometry.

Step 1: convert grams of 6 grams of O_{2} to moles of O_{2}

Step 2: convert moles of O_{2} to moles of NaClO_{3}

Step 3: convert moles of NaClO_{3} to grams of NaClO_{3}

_{The problem may be set up as follows:}

(6.0g O_{2}) X (1 mol O_{2} / 32 g) X (2 mol NaClO_{3} / 3 mol O_{2}) X (106.5g / 1 mol NaClO_{3}) = ___g NaClO_{3}

I will let you do the calculation...