
John H. answered 06/11/21
Asian math tutor who shows you how to solve problems
Heya.
So a sequence is just a bunch of numbers that are changing in some order.
The nth term is just a way of saying the 1st term, 2nd term, 3rd term, etc. where n = 1, 2, 3, etc.
an represents the value at the nth term (1st term, 2nd term, etc.)
In our sequence here: 5, 3, 1, ...
The 1st term (at n = 1) is a1, which is 5
The 2nd term (at n = 2) is a2, which is 3
etc.
So the first thing you want to do in a problem with sequences is look for a pattern.
Here we see that each term decreases by 2.
5
5 - 2 = 3
3 - 2 = 1
1 - 2 = -1
etc.
When each term in a sequence goes down or up by the same amount, it means that each term can be represented by n multiplied by that amount.
So as a simple example to demonstrate this, if a sequence was an = 2n
The 1st term (n=1) would be a1 = 2(1) = 2
The 2nd term (n=2) would be a2 = 2(2) = 4
The 3rd term (n=3) would be a3 = 2(3) = 6
In the sequence 2, 4, 6, ... we can see that each term increases by 2.
Since in our sequence, each term decreases by 2, we can represent this as -2n.
Given that the question is multiple choice, only one of the options has -2n, choice C, and therefore must be the correct answer. However, we will continue explaining how to get the answer completely.
So we know that -2n must be in the equation, but if the sequence were simply an = -2n, when we plug in at n = 1 (the first term), we get a1 = -2. And -2 definitely does not equal 5.
So we know that the first term must have some constant added to it, in order to get to 5.
We express that as:
an = -2n + x, where x is the constant that is added to the term.
Now we can work backwards, from the fact that the first term is 5.
a1 = 5
a1 = -2(1) + x | I'm just replacing the formula above with n = 1 for the first term
5 = -2(1) + x | Now we just solve for x
5 = -2 + x
7 = x
Great! Now we know our constant that is added is 7.
We can put that back into the original equation:
an = -2n + 7
an = 7 - 2n
If we want to double check, we can check the 2nd and 3rd terms.
2nd term: a2 = 7 - 2(2) = 7 - 4 = 3
3rd term: a3 = 7 - 2(3) = 7 - 6 = 1