2 C2H6 + 7O2 = 4 CO2 + 6 H2O If 0.31 moles of H 2 O were produced, how many moles of carbon dioxide would also have been produced?

Question

Grateful for any help given!

Answer 1

you can use the coefficients in the original equation to find the mole ratio that you need to convert this over

0.31 moles H₂O x (4 moles CO₂/6 moles H₂O) = 0.2067

meaning that approximately 0.21 moles of CO₂ would have been produced

Answer 2

Good morning. This moles-to-moles problem will only require one step.

The coefficients in the balanced equation show us that for every 6 moles of water that are produced, 4 moles of carbon dioxide are produced.

We can set up the following equation to solve for moles of carbon dioxide produced:

0.31 mol H₂O X 4 mol CO₂ / 6 mol H₂O = ___________ moles of CO₂

Hopefully that helps!