Inactive Tutor answered 06/09/21
-5x^2 + 2x + 5
5x^2 -2x -5 = 0
x = 2/10 + or - (1/10)sqr(4+100) = 1/5 + or - sqr(104)/10 = 1/5 + or - sqr26/5
=(1+sqr26)/5
C and D are sort of close, just off by .2, but E is best answer
Peter M.
asked 06/09/21The solution contains a reduced fraction ± another reduced fraction with a radical numerator. What is this fraction with a radical numerator?
(A) ± (2√6 i)/5
(B) ± (2√26)/13
(C) ± (√26 i)/5
(D) ± (√26)/5
(E) none of these
Inactive Tutor answered 06/09/21
-5x^2 + 2x + 5
5x^2 -2x -5 = 0
x = 2/10 + or - (1/10)sqr(4+100) = 1/5 + or - sqr(104)/10 = 1/5 + or - sqr26/5
=(1+sqr26)/5
C and D are sort of close, just off by .2, but E is best answer
Inactive Tutor answered 06/09/21
-5x^2+5=-2x
-5x^2+2x+5=0
5x^2-2x-5=0
solve using quadratic formula
a= 5, b=-2 and c=-5
x1=(1+sqrt(26))/5
x2=(1+sqrt(26))/5
Answer: (E) none of these
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Peter M.
Answer E was incorrect. I'm guessing it was D. Thanks anyway for your help06/09/21