the log of a product = the sum of the log of each factor of the product
logxy^2 = logx + logy^2
You can also convert the exponent to a coefficent, so logy^2 = 2logy
thus logxy^2 = logx + 2logy
(1/2)logx - logy = log(sqrx) - log y = log(sqrx/y)
Vanessa C.
asked 06/07/211) Expand the logarithmic expression log xy^2. *show your work*
2) Condense the logarithmic expression 1/2 log x - log y to a single logarithmic. *show your work*
the log of a product = the sum of the log of each factor of the product
logxy^2 = logx + logy^2
You can also convert the exponent to a coefficent, so logy^2 = 2logy
thus logxy^2 = logx + 2logy
(1/2)logx - logy = log(sqrx) - log y = log(sqrx/y)
Brent K. answered 06/07/21
Applied Math PhD
1) log(xy^2) = log(x)+log(y^2) = log(x) + 2log(y)
2) 1/2 log(x) - log(y) = log(x^(1/2)) - log(y) = log( (x^(1/2))/y)
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