110.4g HNO3/ (1+14+3(16))=1.6727 mol HNO3
1.6727 mol HNO3 (2 mol H2O / 6 mol HNO3) = 0.55757 mol H2O = 0.6 mol H2O
Lana T.
asked 06/03/21In the above equation how many moles of water can be made when 110.4 grams of HNO3 are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element | Molar Mass |
Hydrogen | 1 |
Nitrogen | 14 |
Sulfur | 32 |
Oxygen | 16 |
please help me pleas
110.4g HNO3/ (1+14+3(16))=1.6727 mol HNO3
1.6727 mol HNO3 (2 mol H2O / 6 mol HNO3) = 0.55757 mol H2O = 0.6 mol H2O
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