
Mark M. answered 06/02/21
Mathematics Teacher - NCLB Highly Qualified
5 cos (2t) = 5 sin2 (t) + 1
5(1 - 2 sin2 (t)) = 5 sin2 (t) + 1 Double angle formula
5 - 10 sin2 (t) = 5 sin2 (t) + 1
4 = 15 sin2 (t)
4 / 15 = sin2 (t)
±2√15 / 15 = sin (t)
Cassandra K.
asked 06/02/21~Solve 5 cos ( 2 t ) = 5 sin ^ 2 ( t ) + 1 for all solutions 0≤ t <2π
t =
Give your answers accurate to at least 2 decimal places, as a list separated by commas
Mark M. answered 06/02/21
Mathematics Teacher - NCLB Highly Qualified
5 cos (2t) = 5 sin2 (t) + 1
5(1 - 2 sin2 (t)) = 5 sin2 (t) + 1 Double angle formula
5 - 10 sin2 (t) = 5 sin2 (t) + 1
4 = 15 sin2 (t)
4 / 15 = sin2 (t)
±2√15 / 15 = sin (t)
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