
Yefim S. answered 06/01/21
Math Tutor with Experience
cos2x = 1 - 2sin2x = 1 - 2(1/4)2 = 7/8 > 0. So, 2x still in quadrant I
tan2x = √1/cos22x - 1 = √(64/49 - 1) = √15/7;
sin2x = tan2x·cos2x = √15/7·7/8 = √15/8
Camila J.
asked 06/01/21If sin x = 1/4 , x in quadrant I, then find (without finding x)
sin(2x)=
cos ( 2 x ) =
tan ( 2 x ) =
Yefim S. answered 06/01/21
Math Tutor with Experience
cos2x = 1 - 2sin2x = 1 - 2(1/4)2 = 7/8 > 0. So, 2x still in quadrant I
tan2x = √1/cos22x - 1 = √(64/49 - 1) = √15/7;
sin2x = tan2x·cos2x = √15/7·7/8 = √15/8
Mark M. answered 06/01/21
Mathematics Teacher - NCLB Highly Qualified
If sin x = 1/4 in QI, cos x = ? (Use Pythagoras)
Now substitute into appropriate formula.
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