Suppose that csc0=22 and that π/2 < 0 < π . Find the values of sin0, cos0, tan0, sec0, and cot0.

Question

sin0=

cos0=

tan0=

sec0=

cot0=

Answer 1

cscx = 22

sinx = 1/cscx = 1/22= 0.045. hypotenuse squared = sum of squares of the other 2 sides

22^2 = 484 = 1^2 + a^2

a^2 = 483

a= sqr483 = about 21.98

cosx = -21.98/22 = about -0.999

secx = 1/cosx = -1.001

tanx = sinx/cosx = (1/22)/-0.999 = -0.046

cotx = 1/tanx = -21.7