(6, 3) and (4, -3) are end points of a circle. Write the equation of the circle.

Answer 1

(x-5)^2 + y^2 = 10 is the circle's equation

(6-5)^2 + 3^2 = 10

(4-5)^2 +(-3)^2 = 10

take the end points (6,3) and (4,-3) and average the coordinates

(6+4)/2 = 5 = the center's x coordinate = h

(3-3)/2 = 0 = the center's y coordinate = k

h=5, k=0, r^2=10

(x-h)^2 + (y-k)^2 = r^2

Answer 2

When you solve this problem you apply the formula.

The equation of a circle formula is:

(x-h)^2+(y-k)^2=r^2

since this problem indicates two coordinates you plug in the values for each coordinates.

(6-3)^2+(4--3)^2=r^2

ANS: (3)^2+(7)^2=r^2