Inactive Tutor answered 05/26/21
x^2 -12x +20
x^2 -12x + 36 +20 -36 (take half of -12, square it to get 36. Add & subtract 36)
(x-6)^2 - 16 The quadratic is now in vertex form, with vertex = (6,-16) = minimum point on the parabola
Marie V.
asked 05/26/21Consider the equation: x^2-12x+20=0
A) First, use the "completing the square" process to write this equation in the form
(x+D)^2=E and enter your results below.
x^2-12x+20=0 is equivalent to:
Solve your equation and enter your answers below as a list of numbers, separated with a comma where necessary.
Inactive Tutor answered 05/26/21
x^2 -12x +20
x^2 -12x + 36 +20 -36 (take half of -12, square it to get 36. Add & subtract 36)
(x-6)^2 - 16 The quadratic is now in vertex form, with vertex = (6,-16) = minimum point on the parabola
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