Age gap ratio math problem.

Question

If a man is currently 3 times as old as his son, and eight years later he is 2.45 times as old as his son, what will be the ratio of their age after 8 more years (16 years to the current time).

Answer 1

M=3S Man is currently 3 times as old as his Son. M=Man's current age, S=Son's current age

In 8 years, the Man is 2.45 times his Son's age

M+8 = 2.45(S+8)

M+8 = 2.45S+ 19.6

3S+8 = 2.45S +19.6

3S-2.45S = 19.6 -8

0.55S = 11.6

S= 11.6/5.5 = 21.1 years old

M=3(2.11) = 63.3 years old

after 8 years M=71.3 and S=29.1

after 16 years M= 79.3 and S=37.1

their ratio of ages in 16 years is 79.3:37.1 = 79.3/37.1 =about 2.137

In 16 years the man will be 2.137 times as old as his son