A straight line passes through the points (5/2, 2) and (-3/2, 1)

Question

A straight line passes through the points (5/2, 2) and (-3/2, 1)

what is the equation of the line and the x intercept?

Answer 1

line through (5/2,2) and (-3/2,1) has slope (2-1)/(5/2+3/2) = 1/4

the line is y=x/4 +b solve for b by plugging in either point

1=-3/8 +b

b = 1+3/8 = 11/8

the line is y=x/4 + 11/8

or if you want to eliminate fractions

8y =2x +11

Answer 2

When given TWO points on a line; you will need to calculate the slope, m and use the point-slope formula to find the equation of the line

To find the slope, m = rise/run, it does NOT matter which point is P₁ and P₂, the slope will be the same.

m = (y₂ - y₁) / (x₂ - x₁)

I use will P₁ = (5/2, 2) and P₂ = (-3/2, 1)

m = (2 - 1) / (5/2 +3/2) = 1/₄

Now use the point-slope formula and use just ONE of the points given and the slope:

(y - y₁) = m(x - x₁)

I will use P₁ = (5/2, 2)

y - 2 = 1/₄(x - 5/2)

y - 2 = 1/₄(x)-5/8

Isolate the y on the LHS by +2 on both sides

y = 1/₄(x) + 11/8 Final Answer

Answer 3

slope is 4 / 1

(y - 1) / (x + 3/2) = 4

Convert toe slope intercept form and answer?