
Mike D. answered 05/18/21
Effective, patient, empathic, math and science tutor
For a given R in [1,5] consider the interval [R, R +dR] where dR is small
Probability the radius is in R, R+dR is dR/[5-1] = dR/4
Corresponding area is πR2
So to find the expected area, multiply probability by area and sum from R=1 to 5 (so integrate)
So 1/4 πR2 integrated from R=1 to R=5 so π/4 [ R3/3 ] = π/12 [ 53 - 13]
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E(R) = (5-1) / 2 = 3
So clearly this isn't true.
Nunu D.
check out the other questions out05/18/21