
Anthony T. answered 05/12/21
Patient Science Tutor
As the reaction went to completion, ΔG < 0. The reaction is endothermic as the vessel cooled, so ΔH is positive.
From the relation ΔG = ΔH -TΔS, if ΔG is < 0 and ΔH is > 0 then ΔS must be > 0, so the fourth choice seems to be correct, ∆So > 0, since the reaction is thermodynamically favorable at 298 K.