Square Array. The existing codetries to make use of a function void squareArray(const int array[], int destination[], int size).

Question

The existing codetries to make use of a function void squareArray(const int array[], int destination[], int size). This function should take each of the size elements from array, square the element, and place the answer into the same location in the destination array

i.e. if array is {1 2 3 4} and size is 4, when your function returns, destination should be {1 4 9 16}.

Code:

#include <iostream>

using namespace std;

//Do not modify anything on or above the line below this

//YOUR_CODE_BELOW

//YOUR_CODE

//YOUR_CODE_ABOVE

//Do not modify anything on or below the line above this

int main()

{

int NUM_VALUES; //cheating to make this flexible

cin >> NUM_VALUES;

int values[NUM_VALUES];

//Read in values

for(int i = 0; i < NUM_VALUES; i++) {

cin >> values[i];

}

int squares[NUM_VALUES];

//Call your function

squareArray(values, squares, NUM_VALUES);

for(int i = 0; i < NUM_VALUES; i++) {

cout << squares[i] << " ";

}

return 0;

}

Answer 1

void squareArray( const int array[], int destination[], int size)

{

for (int iLoop=0; iLoop<size; iLoop++)

{

destination[iLoop] = array[iLoop]*array[iLoop];

}

}