What is the Probability of Union of 5 and 6 Sets? Please answer it urgently.

Question

Probability of Union of 2 Sets

P(A∪B)=P(A)+P(B)−P(A∩B)

Probability of Union of 3 Sets

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C).

Probability of Union of 4 Sets

P (A U B U C U D) = P(A) + P(B) + P(C) +P(D) - P(A ∩ B) - P(A ∩ C) - P(A ∩ D)- P(B ∩ C) - P(B ∩ D) - P(C ∩ D) + P(A ∩ B ∩ C) + P(A ∩ B ∩ D) + P(A ∩ C ∩ D) + P(B ∩ C ∩ D) - P(A ∩ B ∩ C ∩ D).

What is the Probability of Union of 5 Sets?

What is the Probability of Union of 6 Sets?

Please answer it urgently require

Answer 1

5 sets

P(A) + P(B) + ...+P(E) all 5 letters

-P(A∩B) - P(A∩C) - ... - P(D∩E) all 10 two letter combinations A-E

+P(A∩B∩C) + ... + P(C∩D∩E) all 10 three letter combination A-E

-P(A∩B∩C∩D) - P(A∩B∩C∩E) - ... - P(B∩C∩D∩E) all 5 4-letter combinations

+P(A∩B∩C∩D∩E)

6 sets

P(A) + P(B) + ...+P(F) all 6 letters

-P(A∩B) - P(A∩C) - ... - P(E∩F) all 15 two letter combinations A-E

+P(A∩B∩C) + ... + P(D∩E∩F) all 20 three letter combination A-E

-P(A∩B∩C∩D) - P(A∩B∩C∩E) - ... - P(C∩D∩E∩F) all 15 4-letter combinations

+P(A∩B∩C∩D∩E) + +P(A∩B∩C∩D∩F) + ... + P(B∩C∩D∩E∩F) all 6 5-letter combinations

-P(A∩B∩C∩D∩E∩F)

I left it to you to fill in the missing in each row. I gave you a count so you could check that you didn't miss anything.