Inactive Tutor answered 05/06/21
distance = rate of speed times time
d=rt
50T= 175(T-5)
50T = 175T - 875
175T-50T =875
125T = 875
T = 875/125 = 7 hours from when the 1st train left is when they meet
50 x 7 = 350 miles
175(7-5) = 175(2) = 350 miles
Maria V.
asked 05/06/21A train leaves a station and travels north at a speed of 50mph. Five hours later, a second train leaves on a parallel track and travels north at 175mph. How far from the station will they meet
Inactive Tutor answered 05/06/21
distance = rate of speed times time
d=rt
50T= 175(T-5)
50T = 175T - 875
175T-50T =875
125T = 875
T = 875/125 = 7 hours from when the 1st train left is when they meet
50 x 7 = 350 miles
175(7-5) = 175(2) = 350 miles
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