Inactive Tutor answered 05/05/21
.12(x) + .07(5900-x) = 568
.12x -.07x =568 - 5900(,07) = 568-413 = 155
.05x = 155
x = 155/.05 = $3,100 invested at 12%
(5900-x) = $2,800 invested at 7%
.12(3100) + .07(2800) = 568
372 + 196 = 568
Maria V.
asked 05/05/21$5900 is invested, part of it at 12% and part of it at 7%. For a certain year, the total yield is $568. How much is invested at each rate?
Inactive Tutor answered 05/05/21
.12(x) + .07(5900-x) = 568
.12x -.07x =568 - 5900(,07) = 568-413 = 155
.05x = 155
x = 155/.05 = $3,100 invested at 12%
(5900-x) = $2,800 invested at 7%
.12(3100) + .07(2800) = 568
372 + 196 = 568
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