Inactive Tutor answered 05/04/21
Tutor
New to Wyzant
P=62 = 2L+2W
31 = L+W
31 = 3+W + W = 3+2W
2W = 31-3 = 28
W = 28/2 = 14
L = 14+3 = 17
dimensions are 14 feet by 17 feet
Alison M.
asked 05/03/21The perimeter of a rectangular outdoor patio is 62 ft. The length is 3 ft greater than the width. What are the dimensions of the patio?
Inactive Tutor answered 05/04/21
P=62 = 2L+2W
31 = L+W
31 = 3+W + W = 3+2W
2W = 31-3 = 28
W = 28/2 = 14
L = 14+3 = 17
dimensions are 14 feet by 17 feet
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.