An eight-sided die is tossed: S={1,2,3,4,5,6,7,8}. Rounded to the two decimals, find P(Odd | Greater than and equal to 2)

Answer 1

For this question, we need to use the probability formula that takes into account a given value:

P(B|A)= P(A and B) / P(A)

Let's say that P(A) is the probability that the number rolled is greater than or equal to 2 and that P(B) is the probability that the number rolled is odd.

First, we should find the probabilities we need to plug into this function. Let's find P(A) first.

The P(A) is the probability that the die rolls a value greater than or equal to 2. For an 8-sided die, these values are 2, 3, 4, 5, 6, 7, 8, so P(A) must be 7/8.

Now we need to find the value of P(A and B). So, we need to find the results that are both odd, and greater than or equal to 2. The numbers that meet this requirement are 3, 5, and 7, so our P(A and B) must be 3/8.

Now, all we have to do is plug in these values and solve:

P(B|A) = (3/8) / (7/8) = 3/7

So the probability that the die roll is odd given that it is greater than or equal to 2 is 3/7 or 0.43.

Let me know if you have any questions or need clarification!