Dayaan M. answered 08/26/26
Experienced Elementary Math Tutor with 5+ Years of Teaching
In order to set up a problem with three unknowns like this, look for the person that everybody else is being compared to. Notice that Andre is described in terms of Danielle, and Laura is described in terms of Danielle, but Danielle is not described in terms of anyone. That makes Danielle our variable, and it means we only need one variable instead of three.
So let d be the number of cards Danielle has.
Andre has three more than double Danielle, so we double d and then add three:
Andre = 2d + 3
Laura has four fewer than Danielle, so we subtract:
Laura = d - 4
Remember, we know all three collections together come to 43, so we add up everything and set it equal to 43:
d + (2d + 3) + (d - 4) = 43
Now combine like terms. The d, the 2d and the other d give 4d, and the +3 and -4 give -1:
4d - 1 = 43
Adding 1 to both sides and then dividing by 4:
4d = 44
d = 11
Now we go back and answer the actual question, since the problem asked for all three people and not just d. Danielle has 11. Andre has 2(11) + 3 = 25. Laura has 11 - 4 = 7.
It is always worth checking against the original sentence. 11 + 25 + 7 = 43, which matches, and 25 really is three more than double 11.
So, our final answer is that Danielle has 11 cards, Andre has 25, and Laura has 7.