Raymond B. answered 04/28/21
Math, microeconomics or criminal justice
P(A,K,Q,J) = 16/52 = 4/13
P(black card) = 13/52 = 1/4
P(A,K,Q,J and black card) = 4/52 = 1/13
P(A,K,Q,J or black card) = 4/13 + 1/4 - 1/13 = 3/13+1/4 = 12/52+13/52 = 25/52
25/52 = 0.481 = 48.1% chance of either a black card or an A,K,Q, or J
25 cards would be either black or A,K,Q,J. 4x3 + 13 = 25 out of 52
0.48077 = 48.077% if you want 3 decimal places for a percentage