
Robert J. answered 03/13/13
Certified High School AP Calculus and Physics Teacher
You have two more complex solutions.
Use the sum of two cubes' formula,
t^3 + 216 = t^3 + 6^3 = (t+6)(t^2-6t+36) = 0
t + 6 = 0 => t = -6
or
t^2-6t+36 = 0
=> t^2-6t = -36
=> (t-3)^2 = 9-36 = -27
t = 3 +/- 3sqrt(3) i
Courtnee J.
Thanks Anthony! Does that mean it would be (t-216)(t+1)(t-1) or (t-6)(t^2+6t+36)?03/13/13