Paul M. answered 04/13/21
Tutor
New to Wyzant
Assuming that you mean the (x-1) to be the denominator, the only discontinuity in the function occurs at x=1 and this not removable.
Vi D.
asked 04/13/21Paul M. answered 04/13/21
Assuming that you mean the (x-1) to be the denominator, the only discontinuity in the function occurs at x=1 and this not removable.
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