can i please have help precalculus due soon

Question

Put the equation  into the form :

Answer:  =   

Answer 1

This is a "Completing the Square" Example. The best way I know how to do this is to remember the form of a quadratic: ax² + bx + c = y. Your h value will be equal to h = -b/2 which will give you h = -3. Now you have y = (x+3)² + k = y. If you set the 2 equations equal to each other, you can solve for k.

(x+3)² + k = x² + 6x + 5

Expanding the squared term:

x² + 6x + 9 + k = x² + 6x + 5.

Solving for k gives you k = -4.

In total:

y = (x+3)² - 4

Hope this helps