Raymond B. answered 01/11/23
Math, microeconomics or criminal justice
500/4 = 125
125/11.41= 10.9553 meters = length=width
120.0186 m^2 = max area for $500
Emily S.
asked 04/07/21The question is
"You've been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of the premium fencing (only the best for your farm of course) is $11.41 per metre. So with that, and the following equations,
A=l*w
P=2l+2w
Where A is the area, P s the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field. You should encounter a quadratic function, so using a graphing calculator, or an online graphing website will help you see what that looks like. You can then use previously learned methods to fid the maximum of this function"
They did not teach me how to do this please help
Raymond B. answered 01/11/23
Math, microeconomics or criminal justice
500/4 = 125
125/11.41= 10.9553 meters = length=width
120.0186 m^2 = max area for $500
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.