Raymond B. answered 04/07/21
Math, microeconomics or criminal justice
35X + 15(60-X) = 1700
35X-15X = 1700-900
20X = 800
X = 800/20 = 40 gallons for the 35mph car
60-X = 60-40 = 20 gallons for the 15mph car
Sophia A.
asked 04/07/21A family has two cars. The first car has a fuel efficiency of 15
miles per gallon of gas and the second has a fuel efficiency of 35
miles per gallon of gas. During one particular week, the two cars went a combined total of 1700
miles, for a total gas consumption of 60
gallons. How many gallons were consumed by each of the two cars that week?
Raymond B. answered 04/07/21
Math, microeconomics or criminal justice
35X + 15(60-X) = 1700
35X-15X = 1700-900
20X = 800
X = 800/20 = 40 gallons for the 35mph car
60-X = 60-40 = 20 gallons for the 15mph car
Bradford T. answered 04/07/21
Retired Engineer / Upper level math instructor
Let x be the gallons consumed by the first car and y the gallons consumed by the second car.
From the description
x + y = 60 gallons total used by both cars --> y = 60-x
15x + 35y = 1700
15x + 35(60-x) = 1700
15x + 2100-35x = 1700
20x = 400
x = 20
y = 60-20 = 40.
The first car consumed 20 gallons and the second car consumed 40 gallons.
Let x = number of gallons used by the first car and y = number of gallons used by the second car
15x + 35y = 1700
x + y = 60
From the second equation, y = 60 - x.
So, 15x + 35(60 - x) = 1700
-20x = -400
x = 20 gal and y = 40 gal
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