So, in 2 years the population dropped by 180.
180/2 = 90 per year.
1990 was 4 years before 1994.
4980 + 4(90) = 5340
P(t) = 5340 - 90t
The last part is on you.
Adam B.
asked 03/31/21In 1994, the moose population in a park was measured to be 4980. By 1996, the population was measured again to be 4800. If the population continues to change linearly:Find a formula for the moose population, P, in terms of t, the years since 1990.P(t)= What does your model predict the moose population to be in 2003?
So, in 2 years the population dropped by 180.
180/2 = 90 per year.
1990 was 4 years before 1994.
4980 + 4(90) = 5340
P(t) = 5340 - 90t
The last part is on you.
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