Create a unique parabola is the pattern f(x)= ax^2 + bc + c. Describe the direction of the parabola and determine the y intercept and zeros.

Answer 1

y intercept = 1000 or the point (0,1000) = vertex = maximum point

zeros = -1 and +1 or the points (-1,0) and (1,0)

It's a downward opening parabola, axis of symmetry x=0

It's more like a spike shape

y=ax^2 + 1000, solve for a by plugging in either zero

0=a+1000

a =-1000

y=-1000x^2 + 1000 where a=-1000, b =0 and c=1000

the smaller the coefficient of x^2, the more the parabola begins to collapse into just one vertical line

the closer to 0 the value of a, the more the parabola begins to resemble a horizontal line

Answer 2