
Victoria C. answered 03/25/21
Ivy League Student Specializing in MCAT and STEM Tutoring
This is going to be a plug-and-chug kind of situation, where you have to keep track of your x's and your a's.
First, let's find g(x+a). We know that g(x) = x2 - x, but it might be easier to think of it generally as this:
g(input) = (input)2 - (input). This way, we can think of our input as x + a, and have this:
g(x+a) = (x+a)2 - (x+a) = x2 + 2ax + a2 - x - a = x2 + 2ax - x + a2 - a = x2 + (2a - 1)x + (a2 - a)
Now that you know g(x + a), you can subtract g(x), which is just x2 - x from what we got above.
Hope that helps! Let me know if you have any further questions.

Victoria C.
The answer or the ?? in your problem would be the result of subtract g(x) from g(x+a) as follows We know that g(x + a) = x^2 + (2a - 1)x + (a^2-a) and we know that g(x) = x^2 - x Then, we have: g(x+a) - g(x) = x^2 + (2a - 1)x + (a^2 - a) - x^2 + x = 2ax - x + a^2 - a + x = 2ax + a^2 - a Hope that answers your question!03/25/21