What is the concentration of a solution of Ca(OH)2 for which the pH is 11.68?

Question

is my answer of 2.39x10^-3M correct?

Answer 1

pH = 11.68

pOH = 14 - 11.68 = 2.32

[OH^-] = 1x10^-2.32 = 4.79x10^-3 M

Since 1 mol Ca(OH)₂ produces 2 moles OH-, the concentration of Ca(OH)₂ would be 2.39x10^-3 M

YOU ARE CORRECT. KUDOS.