if i have a point (8,-3) that has a slope of -1/4 then how do i write that in standard form? PLS HELP

Answer 1

y = mx + b is standard form for a linear equation with slope=m and y intercept = b

y=(-1/4)x + b, solve for b by plugging in the point x=8, y=-3

-3 = (-1/4)(8) + b

b = -3 +2 = -1

y= (-1/4)x -1 is standard slope intercept form

there is another standard from

x+4y =-4, call it ax+by = c form, but you probably want the y=-x/4 -1 slope intercept form