Tristin S. answered 03/20/21
Recent College Graduate Looking for Opportunities to Tutor Others
1a)P(n) = 10(1.03) P(n-1) or as a function P(n) = 10(1.03)n, where n is the number of years since 1800 and P(n) is the population in millions of people. It's an exponential function? I'm not sure what exactly they're looking for here.
b) The population estimate for 1830 is given as P(30) = 10 (1.03)30≈ 24.27 million people
The population estimate for 1850 is given as P(50) = 10 (1.03)50≈ 43.84 million people
c) This is just asking us to calculate the n for which P(n) = 30
So 30 = 10(1.03)n
3 = 1.03n
Solving this for n, we get n ≈ 37.17, so in the year 1837, it would surpass 30 million according to his estimate.
2a) R(n) = 0.48 + R(n-1), where R(0) = 12. This is a linear sequence. (As a function it is R(n) = 12 + 0.48n, where n is the number of years since 1800)
b) This is simply asking us for R(30) and R(50). R(30) = 12 + 0.48(30) = 26.4 million people and R(50) = 12 + 0.48(50) = 36 million people.
c) Similarly to this problem, this is asking for what n, does R(n) = 30.
30 = 12 + 0.48n
18 = 0.48n
1800 = 48n
1800/48 = n
150 / 4 = n, so 75/2 = 37.5 = n
In this case, it will reach 30 million in the year 1837, but slightly later in the year.
3) To find this point, we simply need to find the point where the functions are equal:
10*(1.03)n = 12 + 0.48n
1.03n = 1.2 + 0.048n
If we solve for n, we get that n ≈ 36.77, so in the year 1836 the point of crisis occurs.
4) It could be that he got the growth constant incorrect. Or simply the fact he didn't take into account things like famines and scarcity of resources and birthrates and the like affect population growth in a somewhat random fashion.
Tristin S.
The first one I made an algebra mistake calculating n in problem 3. It has since been corrected!03/20/21